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Rufina [12.5K]
3 years ago
5

I need help combining functions!

Mathematics
1 answer:
postnew [5]3 years ago
5 0
\bf \begin{cases}
f(x)=\cfrac{2}{x}\\\\
g(x)=\cfrac{x}{x+2}
\end{cases}\qquad g[\quad f(x)\quad ]=\cfrac{[f(x)]}{[f(x)]+2}

\bf (g\circ f)(x)\iff g[\quad f(x)\quad ]=\cfrac{\boxed{\frac{2}{x}}}{\boxed{\frac{2}{x}}+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{\frac{2}{x}}{\frac{2x+2}{x}}\implies g[\quad f(x)\quad ]=\cfrac{2}{x}\cdot \cfrac{x}{2x+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{2x}{2x^2+2x}\implies  g[\quad f(x)\quad ]=\cfrac{2x}{2x(x+1)}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{1}{x+1}
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If the diameter of an entire coconut is 5 inches, and the coconut meat is 1 inch thick, then there is room for approximately (bl
svetoff [14.1K]
The answer is 14.137 cubic inches.

For this case, the radius of whole coconut is 2.5 inches (which is 5 inches / 2).
You have to subtract the thickness of the coconut from this radius for you to get the volume of the space for coconut milk.

new radius = 2.5 - 1 = 1.5 inches

Volume = (4/3)(pi)(r^3)
= (4/3)(pi)(1.5^3)
= 14.137 cubic inches
6 0
3 years ago
Select all the common denominators for 8/3 and 5/6 .......12, 24, 32, 36, 48
BabaBlast [244]
Hello.

The answer to your question is = 
12, 3 x 4 and 6 x 2.
24, 3 x 8 and 6 x  4.
36, 3 x 12 and 6 x 6.
48, 3 x 16 and 6 x 8.

So it's pretty much everything except for 32.
Have a great day!
6 0
4 years ago
Read 2 more answers
Find the distance between (3,4) and (4,-6) if necessary, round to the nearest tenth.
Ratling [72]

Answer:

The distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

Step-by-step explanation:

Given the points

  • (3,4)
  • (4,-6)

The distance 'd' between (3,4) and (4,-6)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

substituting the points values

   =\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}

   =\sqrt{1+10^2}

   =\sqrt{1+100}

   =\sqrt{101}

   =10.0  units (Rounded to the nearest the Tenths Place)

Thus, the distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

4 0
3 years ago
Here are four straight line equations.
AnnyKZ [126]

lines a and d are parallel and lines b and c are parallel

6 0
3 years ago
Un chip tiene un espesor de 0,12 mm y un atomo de cobre mide 0,00000000133 m.¿cuantos atomos se necesita para alinearlos en el e
aleksandr82 [10.1K]

Answer:

El espesor de un chip es de 0.12mm

Y el diámetro de un átomo de cobre, mide aprox:

0.00000000133 m

Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm

Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm

Primero, escribamos ambos valores en las mismas unidades, sabiendo que:

1m = 1000mm

Podemos reescribir:

0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm

Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm

Esto sera igual al cociente entre 0.12mm y  0.00000133mm, esto es:

N = (0.12mm)/(0.00000133mm) = 90,225.6

Redondeamos al próximo número entero:

N = 90,226

Esa es la cantidad de átomos que se necesitan.

7 0
3 years ago
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