Question

You have 846 ml of 3.95 M HCl. Using a volumetric pipet, you take 268 ml of that solution and dilute it to 803 ml in a volumetric flask. Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution?

Answer 1

Answer: The concentration of hydrochloric acid in the final solution is 0.72 M

Explanation:

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 3.95 M

$V_1$ = volume of stock solution = 268 ml

$M_2$ = molarity of diluted solution = ?

$V_2$ = volume of diluted solution = 803 ml

$3.95\times 268=M_2\times 803$

$M_2=1.32M$

Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask.

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 1.32 M

$V_1$ = volume of stock solution = 100 ml

$M_2$ = molarity of diluted solution = ?

$V_2$ = volume of diluted solution = 184 ml

$1.32\times 100=M_2\times 184$

$M_2=0.72M$

Thus concentration of hydrochloric acid in the final solution is 0.72 M