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JulijaS [17]
3 years ago
12

If 100 mL of a 12 M solution of HCl is diluted to a final volume of 500 mL, what would be the final concentration of the diluted

HCl?
Chemistry
1 answer:
AURORKA [14]3 years ago
3 0
Dilution formula:
mv = MV

where one side is concentration × volume BEFORE dilution and the other side is concentration × volume AFTER dilution. 

(100mL) × (12 M) = (500mL) × (X)
(1200 M·mL) = (500mL) × (X)
(1200 M·mL) / (500mL) = X
2.4 M = X

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There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

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There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

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There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

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Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

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3 years ago
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