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JulijaS [17]
3 years ago
12

If 100 mL of a 12 M solution of HCl is diluted to a final volume of 500 mL, what would be the final concentration of the diluted

HCl?
Chemistry
1 answer:
AURORKA [14]3 years ago
3 0
Dilution formula:
mv = MV

where one side is concentration × volume BEFORE dilution and the other side is concentration × volume AFTER dilution. 

(100mL) × (12 M) = (500mL) × (X)
(1200 M·mL) = (500mL) × (X)
(1200 M·mL) / (500mL) = X
2.4 M = X

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Wewaii [24]

Answer:

Explanation:

Atoms are the thing that make up molecules and compounds. Molecules contain two or more atoms and are held together by covalent bonds

7 0
3 years ago
For the reaction of sodium bromide with chlorine gas
lina2011 [118]

The reaction of sodium bromide with chlorine gas is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).

<h3>What is sodium bromide?</h3>

Sodium bromide is an inorganic compound, white, crystalline with high melting point.

The reaction between halogens is redox reaction

Oxidation  – 2Br⁻ ? Br₂ + 2e⁻ loss of electron.

Reduction – Cl₂ + 2e⁻ ? 2Cl⁻ gains of electron.

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7 0
2 years ago
Lipids are a major component of cells?
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8 0
3 years ago
What is the concentration of a lithium hydroxide solution with a pH of 9.25
slavikrds [6]

Answer:

[H+] =5.62*10⁻¹⁰

Explanation:

pH = 9.25

The formula to find pH of a solution is

pH = -Log[H+]

9.25 = -Log[H+]

Take the anti log of both sides

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5 0
3 years ago
A simple of helium measuring 6L was kept at a pressure is of 1.5 atm ,if pressure is doubled what would be its new volume ?
KATRIN_1 [288]

Answer:

3L

Explanation:

The following data were obtained from the question:

V1 (original volume) = 6L

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P2 (new pressure) = 2 x P1 ( since the new pressure is doubled)

P2 = 2 x 1.5

P2 = 3 atm

V2 (new volume) =?

Using the Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:

P1V1 = P2V2

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Divide both side by 3

V2 = (1.5 x 6)/3

V2 = 3L

From our calculations, the new volume will be half the original volume and this will be 3L

6 0
3 years ago
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