If 100 mL of a 12 M solution of HCl is diluted to a final volume of 500 mL, what would be the final concentration of the diluted
1 answer:
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<u>Answer:</u> The molality of non-electrolyte is 24.69 m
<u>Explanation:</u>
We are given:
Mole fraction of saturated aqueous solution = 0.310
This means that 0.310 moles of non-electrolyte is present.
Moles of water (solvent) = 1 - 0.310 = 0.690 moles
To calculate the mass from given number of moles, we use the equation:
Moles of water = 0.690 moles
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
To calculate the molality of solution, we use the equation:
Where,
= Moles of solute (non-electrolyte) = 0.310 moles
= Mass of solvent (water) = 12.42 g
Putting values in above equation, we get:
Hence, the molality of non-electrolyte is 24.69 m