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lisov135 [29]
3 years ago
10

What is the appearance of the signal corresponding to the CH₂ protons in the 1H NMR spectrum of ethyl methyl ether, CH₃CH₂OCH₃?

Chemistry
1 answer:
Tems11 [23]3 years ago
7 0

Answer: option C. a quartet

Explanation:

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Using the spectra data below, which structure best matches this data? c4h8o 1h nmr triplet at 1.05 ppm (3h) singlet at 2.13 ppm
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Answer:

Butan-2-one

Explanation:

1. 1700 cm⁻¹

A strong peak near 1700 cm⁻¹ is almost certainly a carbonyl (C=O) group.

2. Triplet-quartet

A triplet-quartet pattern indicates an ethyl group.

The 2H quartet is a CH₂ adjacent to a CH₃. The peak normally occurs at δ 1.3, but it is shifted 1.2 ppm downfield to δ 2.47 by an adjacent C=O group.

The 3H triplet at δ 1.05 is the methyl group. It, too, is shifted downfield from its normal position at δ 0.9. The effect is smaller, because the methyl group is further from the carbonyl.

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It is shifted 0.8 ppm downfield to δ 2.13 by the adjacent C=O group.

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The identified pieces are CH₃CH₂-, -(CO)-, and -CH₃. There is only one way to put them together: CH₃CH₂-(C=O)-CH₃.

The compound is butan-2-one.

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