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3 years ago

Diffusion occurs faster in gases than in liquids because _____.

Chemistry

2 answers:

djverab [1.8K]3 years ago

7 0

Explanation:

In liquids molecules are somewhat tigthly held together compared to gas molecules. It results decrease in kinetic energy of liquid molecules

While in gases, molecules are arranged in a zigzag pattern and move freely. Hence kinetic energy is more and diffusion rate is also more for gas molecules than liquid molecules.

zalisa [80]3 years ago

6 0

Diffusion occurs faster in a gas than in liquids because in a liquid the molecules are closser together and in a gas they are farther appart

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Who are the scientists that contributed in arranging of the periodic table?

Irina-Kira [14]

In 1869 Russian chemist DIMITRI MENDELEEV started the development of the periodic table,arranging chemical elements by atomic mass. He predicted the discovery of other elements and left spaces open in his periodic table for them. HOPE THIS HELPSS HAVE A GREAT DAY <333

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2 years ago

Which is a higher concentration, 10-9 M or 10-8 M? Explain.

andreyandreev [35.5K]

Answer:

10-9 Millimeters/liters

Explanation:

Because 10-9 M Is more than 10-8 M

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3 years ago

If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced

Fed [463]

Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

Moles of O₂ = 499 mol

Moles of CO₂ = ?

First of all we will write the balance chemical equation.

2C₆H₁₄O₂ + 17O₂ → 14CO₂ + 12H₂O

moles of C₆H₁₄O₂ = mass × molar mass

moles of C₆H₁₄O₂ = 16.5 g × 118 g/mol

moles of C₆H₁₄O₂ = 1947 mol

Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

O₂ : CO₂

17 : 14

499 : 14/17× 499 = 410.9 moles

C₆H₁₄O₂ : CO₂

2 : 14

1947 : 14/2× 1947 = 13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

5 0

3 years ago

Read 2 more answers

What are the chemical properties of beryllium phosphide??

o-na [289]

Answer:

Forms ionic bonds, insoluble, doesn't participate in single or double displacement reactions, non-reactive, high heat of combustion

Explanation:

Beryllium is a metal, since it belongs to group 2A, the alkaline earth metals. It has a total of 2 valence electrons.

Phosphorus, on the other hand, belongs to group 5A and has a total of 5 valence electrons.

We have a compound which has a metal in it, therefore, it's an ionic compound. Beryllium, our metal, loses its 2 electrons to gain an octet and phosphorus, our nonmetal, should gain 3 electrons to have an octet. The oxidation states are +2 and -3 respectively. This means we need 3 beryllium cations and 2 phosphide anions in our formula $Be_3P_2$ .

Beryllium phosphide would be expected to be insoluble, as only beryllium chloride, fluoride, nitrate, phosphate and sulfate are soluble substances, while the remaining ones are expected to be insoluble.

Due to its insolubility, beryllium phosphide would not participate in any ionic reactions, such as single displacement or double displacement.

Since it's insoluble, we expect this compound to be chemically stable and not reactive. This implies that if we wanted to burn it, the heat of combustion would be very high, as a lot of energy would be needed to be supplied in an endothermic reaction in order to burn it.

8 0

2 years ago

For the reaction where Δn=−1Δn=−1 , what happens after in increase in volume? ????KQ>K so the reaction shifts toward reactant

Alex787 [66]

Answer:

Explanation:

In general, an increase in pressure (decrease in volume) favors the net reaction that decreases the total number of moles of gases, and a decrease in pressure (increase in volume) favors the net reaction that increases the total number of moles of gases.

Δn= b - a

Δn= moles of gaseous products - moles of gaseous reactants

Therefore, <u>after the increase in volume</u>:

If Δn= −1 ⇒ there are more moles of gaseous reactants than gaseous products. The equilibrium will be shifted towards the products, that is, from left to right, and K>Q.
If Δn= 0 ⇒ there is the same amount of gaseous moles, both in products and reactants. The system is at equilibrium and K=Q.
Δn= +1 ⇒ there are more moles of gaseous products than gaseous reactants. The equilibrium will be shifted towards the reactants, that is, from right to left, and K<Q.

8 0

2 years ago