The values of N, log N and ln N are all worked out below.
We have the number N as 8.99
hence;
1) lnN = ln(8.99) = 2.196
log N = log (8.99) = 0.954
2) If we have ln N as 3.949
N = e^3.949 = 51.88
So;
log N = log (51.88) = 1.715
3) log N = 0.134
N = Antilog (0.134 ) = 1.36
ln N = ln (1.36) = 0.307
Learn more: brainly.com/question/4210362
That isn't worded as a question and didn't make sense.
Answer:
see explanation
Explanation:
To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.
P₄ + 5O₂ => 2P₂O₅
12/1 = 12 15/5 = 3
O₂ is the limiting reactant. P₄ will be in excess when rxn stops.
Answer:
= 654.5 g NaNO3
Explanation:
Molarity = Moles/ volume
Volume = 3.5 L
Molarity = 2.2 M
Therefore;
Moles = Molarity × volume
= 3.5 L × 2.2 M
= 7.7 moles
But 1 mole of NaNO3 is 85 g/mol
Mass of NaNO3 = 85 g/mole × 7.7 moles
= 654.5 g NaNO3