The correct answer is C: 1/(x + 4)(x - 5)
Why? Well, let's first simplify x^2 - 3x - 10 and x^2 + x - 12; the two denominators. Each of these should become an (x +/- number), and to figure out the number, as well as whether it is positive or negative, we can do a simple trick
Look at the factors of the right number (In this case, -10 and -12)
-10 -12
1 * -10 1 * -12
-1 * 10 -1 * 12
-2 * 5 -2 * 6
2 * -5 2 * -6
-3 * 4
4 * -3
Now for part 2
Which of these pairs add up to the middle number? One of the pairs of -10 should make -3, and likewise, one of the pairs of -12 should make 1 (when x has no number in front of it you may safely assume it is 1).
2 - 5 = -3 and 4 - 3 = 1, so we now know that the 2 fraction equations simplified is
x + 2 / (x + 2)(x - 5) * x - 3/(x -3)(x + 4)
Notice anything repeating? As long as they are apart of the same fraction, we can cross out anything that has the same x - number. Crossing out both x + 2 and x - 3, we now simply have x - 5 * x + 4. Because we crossed out both numerators, the top numbers both become 1, thus giving our answer, C.
You've given us a single term of an arithmetic series. So far, there are an infinite number of different series that it could be a member of. ... In fact, ANY function f (n) for which f (7) = 54 produces a suitable series for whole-number values of 'n'. Here are a few: ... T(n) = n + 47. ... T (n) = 8n - 2. ... T (n) = -10n + 124 .
Answer:
Step-by-step explanation:
The given expresion is:
We want to find the first step in simplifying the above expression based on order of operations.
We use PEDMAS, so we deal with parenthesis first.
Within the parenthesis, we still need to multiply first to get:
Vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function. (They can also arise in other contexts, such as logarithms, but you'll almost certainly first encounter asymptotes in the context of
Assuming that the null hypothesis is true, then<u> p-Value</u> is the probability of observing a value of the test statistic that is at least as extreme as the value actually computed from the sample data.
Step-by-step explanation:
<u>The p-value is the probability that a random sample that is selected produces as the value of the test statistic is at least as extreme as the observed value when H0 is true.</u>
<u>The p-value as measure of how surprising our result is if the null hypothesis is true.</u>
So ,we can state that- Assuming that the null hypothesis is true, then<u> p-Value</u> is the probability of observing a value of the test statistic that is at least as extreme as the value actually computed from the sample data.
