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3 years ago

Hi friends. Which is a common denominator of 1/4 and 3/5? Please explain how you got this answer.

Mathematics

2 answers:

Ivahew [28]3 years ago

7 0

Answer:

5/20 and 12/20

Step-by-step explanation:

To find the LCD ( Least Common Denominator) you need to find a multiple that is in the least amount. You first start by listing common multiples.

For 1/4 there are 8, 12, 16, and 20.

You get this by finding multiples of 4.

For 3/5 there is 10, 15, 20, and 25.

The Common multiple is 20 and it is the least.

This means 20 is the now the common denominator.

Multiply to get the equivalent self.

1/4 = 5/20, you multiply by 5/5.

3/5 = 12/20, you multiply by 4/4

The fraction have the same value because you multiply them by 1.

Lilit [14]3 years ago

7 0

Answer:

list the multiples

4,8,12,16,20,24,28,32,36,40

5,10,15,20,25,30,35,40,45,50

They both have 20 and 40 as a common factor. 20 is the smallest common factor.

If you have any questions pls ask

Step-by-step explanation:

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3 years ago

Which of the following statements would be correct to use when proving that limx→4(3x−4)=8?

Fudgin [204]

Answer:

Option c

Step-by-step explanation:

given that limit x tending to 4 of the function (3x-4) is 8

This implies for all values of x such that for epsilon >0 arbitrary small ,

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|f(x)-8|<3epsilon

this is equivalent to the option c.

Proof:

Consider

$||x-4||$

Hence it follows that option C is right.

3 0

3 years ago

Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$

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2 years ago