The total ball in the bag is 4 + 2 = 6 balls. Their are 4 red balls and 2 blue balls.
If they are drawn singly the probability that 2 blue balls are counted can be expressed as follows
5,000 tens = (5,000 x 10)
To find out how many thousands are in it,
just divide:
(5,000 x 10) / (1,000) = (5 x 10) = 50 of them .
The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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#1 is 2 #2 is 6 i dont know 3
