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2 years ago

Use Multistep Pythagorean Theorem to answer

Mathematics

1 answer:

uranmaximum [27]2 years ago

6 0

Answer:

√5

Step-by-step explanation:

I think that is the answer I never come to such a question of changing things to radical form but I guess 5 cannot be multiplied by a number such that it has a square root so the answer is that√5

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The base of a triangle is 10 cm

bonufazy [111]

I’m not sure about this question

4 0

2 years ago

Combine the like terms -5.4v plus 0.3v

VladimirAG [237]

-5.4v+0.3v= -5.1v

Because both numbers have a common variable of 'v,' they can be combined.

6 0

3 years ago

Patty sells pies to customers at a price of $16 per pie. She starts the day with $90 in her cash register. How many pies does Pa

Gala2k [10]

There are two ways you can do this question, you can one, subtract the 90 from 538 which should give you 448 then you can divide 448 by 16. Your answer should be 28 pies

5 0

1 year ago

Reflect (-8, -9) over the Y-axis. Where does it end up?

mina [271]

Answer:

(8, - 9 )

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

(- 8, - 9 ) → (8, - 9 )

8 0

3 years ago

The position of an object at time t is given by s(t) = 6 - 14t. Find the instantaneous velocity at t = 6 by finding the derivati

nikdorinn [45]

Answer:

<em>It results -14 in either way</em>

Step-by-step explanation:

<u>Velocity As A Rate Of Change </u>

The velocity of an object can be computed as the rate of change of its displacement (or position taken as a vector) over time. If we compute it as a derivative, it's called instantaneous velocity, and if computed as the slope of the function (difference quotient) at a certain point it's the average velocity

The position of the object as a function of time is

$\displaystyle s(t)=6-14t$

Computing the derivative

$\displaystyle s'(t)=-14$

We can see it's a constant value. If we use the slope or rate of change:

$\displaystyle v=\frac{s_2-s_1}{t_2-t_1}$

Now let's fix two values for time

$\displaystyle t_1=5\ sec,\ t_2=8\ sec$

and compute the corresponding positions, by using the given function

$\displaystyle s_1=6-14(5)=-64$

$\displaystyle s_2=6-14(8)=-106$

Now we compute the average velocity

$\displaystyle v=\frac{-106-(-64)}{8-5}$

$\displaystyle v=\frac{-106+64}{3}=\frac{-42}{3}$

$\displaystyle v=-14$

We get the very same result in both ways to compute v. It happens because the position is related with time as a linear function, it's called a constant velocity motion.

7 0

3 years ago