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2 years ago

100 POINTS IF U GET THIS RIGHT!

Mathematics

1 answer:

Sloan [31]2 years ago

4 0

Answer:

5/6 km²

Step-by-step explanation:

<u>Use the area equation:</u>

A = 1/2bh

<u>Substitute values:</u>

A = 1/2* 1 2/3 * 1 = 1/2*5/3 = 5/6 km²

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A rectangular container is 25 cm long and 20 cm wide. If it holds 1 liter of water when full, what is its height?

snow_tiger [21]

Answer: $2\ cm$

Step-by-step explanation:

The volume of a rectangular prism can be calculated with the following formula:

$V=lwh$

Where "l" is the lenght, "w" is the width and "h" is the height.

You know that the lenght of this rectangular container is 25 centimeters and its width is 20 centimeters. Then:

$l=25\ cm\\\\w=20\ cm$

If it holds 1 liter of water when full, then its volume is:

$V=1\ L$

Since:

$1\ L=1,000\ cm^3$

The volume of the container in cubic centimeters is:

$V=1,000\ cm^3$

Now, in order to find the height of the container, you need to solve for "h" from the formula:

$h=\frac{V}{lw}$

Substituting values, you get that its height is:

$h=\frac{1,000\ cm^3}{(25\ cm)(20\ cm)}\\\\h=2\ cm$

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3 years ago

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Solve the following equation by completing the square. 1/4x^2+x+1/4=0

fenix001 [56]

Answer:

D. X=-2+sqrt(3) or -2-sqrt(3)

$x_{1} =-2+\sqrt{3} \\x_{2} =-2-\sqrt{3}$

Step-by-step explanation:

Quadratic Equation given:

$\frac{1}{4} x^2+x+\frac{1}{4}=0$

In order to get rid of the fractions, multiply both sides by 4.

$\frac{1}{4}x^2\cdot \:4+x\cdot \:4+\frac{1}{4}\cdot \:4=0\cdot \:4$

We get:

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$x^2+4x+4-4+1=0$

Completing the square:

$(x+2)^2-4+1=0\\$

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$(x+2)^2=3$

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$x=-2\pm\sqrt{3}$

$x_{1} =-2+\sqrt{3} \\x_{2} =-2-\sqrt{3}$

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2 years ago

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Answer:

The Answer is B Marnie will have to share her card account information.

Plus I took this test so

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3 years ago

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Sara goes on a slingshot ride in an amusement park. she is strapped into a spherical ball that has a radius of centimeters. what

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I hope this helps you

volume of sphere =4/3.pi.r^3

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3 years ago

Phillip claimed that the expression − p + 5 + p is positive for any value of p. Determine whether Phillip’s statement is always

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Answer:

always true.

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