Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}
The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go
{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers
6/10
.6
If i'm wrong, sorry, haven't done this kind of stuff in a while
Answer:
622.27
Step-by-step explanation:
- $87.45 + (- $24.76) + (-17.29) = $-129.5
$143.87 + $348.90 = $492.77
492.77 - (-129.5) = 622.27
Answer:
Step-by-step explanation:
x = small barrettes
y = large barrettes
13x + 11y = 142.......multiply by -1
13x + 12y = 149
-----------------------
-13x - 11y = -142 (result of multiplying by -1)
13x + 12y = 149
------------------------add
y = 7..........large barrettes used 7 yards
13x + 11y = 142
13x + 11(7) = 142
13x + 77 = 142
13x = 142 - 77
13x = 65
x = 65/13
x = 5........small barrettes used 5 yards