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miss Akunina [59]
3 years ago
13

Find the slope! need help!

Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

-1/2 is the slope

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What is the slope of a graph?​
e-lub [12.9K]

Answer:

Image result for what is the slope of a graph?​

The slope of a line is rise over run. Learn how to calculate the slope of the line in a graph by finding the change in y and the change in x.

Step-by-step explanation:

6 0
3 years ago
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What is the area of the rectangle below?
egoroff_w [7]

Answer:

52 if im wrong sorry :(

Step-by-step explanation:

8 0
3 years ago
Answer please I need before Friday
aleksley [76]

Answer:

hiiii

Step-by-step explanation:

but u have posted all the pictures upside down so can't understand anything

4 0
3 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
If you can tell me the answer please do i need help besties​
DerKrebs [107]

Answer:

51

Step-by-step explanation:

8.5/1

and

x/6

cross multiply

51=x

7 0
3 years ago
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