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Alex
3 years ago
12

What do you know about tides?

Physics
1 answer:
Neporo4naja [7]3 years ago
8 0

Tides are the rise and fall of sea levels caused by the combined effects of the gravitational forces exerted by the Moon and the Sun, and the rotation of the Earth. Tide tables can be used to find the predicted times and amplitude (or "tidal range") of tides at any given locale.

For further expiation please contact me at 678-987-2411. Disclaimer(This is not a real number)

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A car traveled 176 miles on 6.4 gallons of fuel the car averaged how many miles per gallon
earnstyle [38]
It would be 27.5 miles per gallon
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3 years ago
Physical Properties include...
3241004551 [841]

and C. taste, odor, and texture

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3 years ago
A merry go round exerts a force of 1000 N on a rider on the
SVEN [57.7K]

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r

Where;

m = The mass of the person

v = The velocity of the person

F_c = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for  the centripetal force, we have;

F_c = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

3 0
3 years ago
A boy twirls a 15-lb bucket of water in a vertical circle. If the radius of curvature of the path is 4 ft, determine the minimum
chubhunter [2.5K]

Answer:

11.35 m/s

Explanation:

Given,

Weight of the bucket = 15 lb

radius of curvature, r = 4 ft

Minimum speed of the bucket = ?

Using equation of centripetal acceleration

W=\dfrac{mv^2}{R}

15=\dfrac{\dfrac{m}{g}\times v^2}{4}

15=\dfrac{\dfrac{15}{32.2}\times v^2}{4}

v^2 = 128.8

v = 11.35\ m/s

Speed of the bucket  = 11.35 m/s

5 0
3 years ago
a train traveling at 30m/s comes to a complete stop in 20 sec.how far did the train go during the deceleration
elixir [45]

Answer:

600m

Explanation:

v=30m/s

t=20s

s=VT

20×30=600m

3 0
3 years ago
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