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lianna [129]
4 years ago
8

Describe how the speed of light waves changes when they travel from air into a

Physics
2 answers:
Naddika [18.5K]4 years ago
5 0

Answer:

Speed of light decreases when it goes from a rarer medium to denser medium and increases when it travels from denser to rarer.

Explanation:

when light will fall on aquarium the glass wall and water inside it are denser compared to the air outside. so, the ray will refract from its original path (bending towards the normal) and decrease its speed. The reverse happens when it travels out of aquarium. the air is less dense compared to the water and glass so it will increase the speed.

Stolb23 [73]4 years ago
3 0

Answer:

speed of light waves change when they travel in air to aquarium because want's the light hits the water you see bunches of color along with bigger looking objects

Explanation:

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Two workers pull horizontally on a heavy box. but one pulls twice as hard as the other. The larger pull is directed at 21.0° wes
pantera1 [17]

Answer:

The  magnitude of F1 is

|F1|=358.74 \ N

The magnitude of F2 is

|F2|=179.37\ N

And the direction of F2 is

\alpha = 44.214^o

Explanation:

<u>Net Force </u>

Forces are represented as vectors since they have magnitude and direction. The diagram of forces is shown in the figure below.  

The larger pull F1 is directed 21° west of north and is represented with the blue arrow. The other pull F2 is directed to an unspecified direction (red arrow). Since the resultant Ft (black arrow) is pointed North, the second force must be in the first quadrant. We must find out the magnitude and angle of this force.  

Following the diagram, the sum of the vector components in the x-axis of F1 and F2 must be zero:

\displaystyle -2F\ sin21^o+F\ cos\alpha =0

The sum of the vertical components of F1 and F2 must equal the total force Ft

\displaystyle -2F\ cos21^o+F\ sin\alpha =460

Solving for \alpha in the first equation

\displaystyle cos\alpha =\frac{2F\ sin21^o}{F}=2sin21^o

\displaystyle cos\alpha =0.717=>\alpha =44.214^o

\displaystyle F(2cos21^o+sin\alpha)=460

\displaystyle F=\frac{460}{2cos21^o+sin\alpha}

\displaystyle F=\frac{460}{2cos21^o+sin44.214^o}

\displaystyle F=179.37\ N

The  magnitude of F1 is

|F1|=2*F=358.74 \ N

The magnitude of F2 is

|F2|=179.37\ N

And the direction of F2 is

\alpha = 44.214^o

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3 years ago
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