Answer:
80
Explanation:
<em>the </em><em>mechanical</em><em> </em><em>advantage</em><em> </em><em>is </em><em>the </em><em>ratio </em><em>of </em><em>the </em><em>load </em><em>to </em><em>the </em><em>effort</em><em> </em><em>so </em><em>it </em><em>doesn't</em><em> </em><em>have </em><em>units.</em><em>t</em><em>o</em><em> </em><em>calculate</em><em> </em><em>it </em><em>you </em><em>use </em><em>the </em><em>formula</em>
<em>mechanical</em><em> advantage</em><em>=</em><em>load/</em><em>effort</em>
<em>in </em><em>this</em><em> case</em><em> </em><em>the </em><em>load </em><em>is </em><em>6</em><em>0</em><em>0</em><em>0</em><em>N</em><em> </em><em>and </em><em>the </em><em>effort</em><em> </em><em>is </em><em>7</em><em>5</em><em>N</em>
<em>Ma=</em><em>6</em><em>0</em><em>0</em><em>0</em><em>/</em><em>7</em><em>5</em>
<em>=</em><em>8</em><em>0</em>
<em>I </em><em>hope</em><em> this</em><em> helps</em>
<em>The answer you are looking for is: </em>
<em><u>True</u>
Hope that helps!! </em>
<em>Have a wonderful day!! </em>
<em>If you ever need anything feel free to ask me!!</em>
Answer:
<h2>c. remain constant</h2>
Explanation:
Such type of field that is created by the magnetic condition is known as magnetic field. Such type of the developed by electrical condition and some other ways. This filed has many important roles in electrical engineering and some other fields.
When any magnetic field acts in perpendicular condition then no work is done by the field. Thus the kinetic energy and speed of the particle remain in constant condition.
Answer:
The image distance from right lens is 2.86 cm and image is real.
Explanation:
Given that,
Focal length of left lens = 10 cm
Focal length of right lens = 5 cm
Distance between the lenses d= 15 cm
Object distance = 50 cm
We need to calculate the image distance from left lens
Using formula of lens

Put the value into the formula



We need to calculate the image distance from right lens
The object distance will be

Using formula of lens

Put the value into the formula



The image is real.
Hence, The image distance from right lens is 2.86 cm and image is real.
Answer:
Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.
i hope this helps your answer