Ask question

Ask question

All categories

3 years ago

13

In one poem, which "poor and country-bred" figure is said to have caused smart people to "laugh at him" and ask, "How can so ver

y plain a man be great?"
A.
Walt Whitman

B.
George Washington

C.
Christopher Columbus

D.
Abraham Lincoln

1 answer:

Kay [80]3 years ago

6 0

Abraham Lincoln, i've read that story a long time ago myself and I remember who said that.

You might be interested in

A jar contains 17 orange, 7 pink, and 4 black marbles. A marble is drawn at random. What is the probability that the marble is p

Anon25 [30]

17+7+4=28

17+7=24

24 out of 28

3 0

3 years ago

Read 2 more answers

Select the Equivalent Expression!

iVinArrow [24]

Answer:

C is correct

Step-by-step explanation:

7 0

3 years ago

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

8 0

3 years ago

Read 2 more answers

A local am radio station broadcasts at a frequency of 764 khz. calculate the energy of the frequency at which it is broadcasting

pentagon [3]

The frequency of the emitted radio waves is:
$f=764 kHz = 7.64 \cdot 10^5 Hz$

The energy of a photon is given by:
$E=hf$
where h is the Planck constant and f is the photon frequency. Using the frequency given by the problem, we can find the energy of each photon of this radiation:
$E=hf=(6.6 \cdot 10^{-34} Js)(7.64 \cdot 10^5 Hz)=5.04 \cdot 10^{-28} J=5.04 \cdot 10^{-31} kJ$

7 0

3 years ago

Help me with #19, please

densk [106]

You would pay 6 dollars

4 0

3 years ago