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AURORKA [14]
3 years ago
5

Question 2 Which figures demonstrate a single rotation? Select each correct answer.

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0

The first one u circled is a single rotation

adelina 88 [10]3 years ago
3 0

Answer:

The upper left figure has a single rotation.

Step-by-step explanation:

In math and geometry single rotation is what we call a figure that has been rotated by only 90º from an original point and it is usually measured to the right, so in this case from the option the figure that has been rotated only 90º is the one in the upper left corner of the image.

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A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.
iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- |E\ n\ B|

- |B|

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

B = \{6\}

E = \{2,4,6\}

Calculating the size of |E n B|

|E n B| = \{2,4,6\}\ n\ \{6\}

|E n B| = \{2,4,6\}

<em>The size = 3 because it contains 3 possible outcomes</em>

Calculating the size of |B|

B = \{6\}

<em>The size = 1 because it contains 1 possible outcome</em>

8 0
3 years ago
tensor-on-tensor regression: riemannian optimization, over-parameterization, statistical-computational gap and their interplay
Contact [7]

The purpose of the tensor-on-tensor regression, which we examine, is to relate tensor responses to tensor covariates with a low Tucker rank parameter tensor/matrix without being aware of its intrinsic rank beforehand.

By examining the impact of rank over-parameterization, we suggest the Riemannian Gradient Descent (RGD) and Riemannian Gauss-Newton (RGN) methods to address the problem of unknown rank. By demonstrating that RGD and RGN, respectively, converge linearly and quadratically to a statistically optimal estimate in both rank correctly-parameterized and over-parameterized scenarios, we offer the first convergence guarantee for the generic tensor-on-tensor regression. According to our theory, Riemannian optimization techniques automatically adjust to over-parameterization without requiring implementation changes.

Learn more about tensor-on-tensor here

brainly.com/question/16382372

#SPJ4

7 0
2 years ago
Plzzzzzzzzzzzzzzzzzzzzzzzzz
AleksandrR [38]

Answer:

i dont know what it means by expand but i will simplify it

it would simplify to 16x-18

Step-by-step explanation:

5(2x-1) + 2(3x-6)

10x-5+6x-12

10x+6x-5-12

16x-18

7 0
2 years ago
(8–9a)a=−40+(6–3a)(6+3a)
elena-14-01-66 [18.8K]

Answer:

a=-0.5

Step-by-step explanation:

Distributive property for left side, difference of squares for right side.

8a-9a^2=-40+36-9a^2

-9a^2 cancels out

8a=-4

a=-0.5

8 0
3 years ago
Read 2 more answers
PLEASE HELP! Find the distance between each pair of points. Round your answers to the nearest tenth.
strojnjashka [21]
A.
Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\  = \sqrt{\left( -4 - \left( -5 \right) \right)^2 + \left( -2 - \left( -3 \right) \right)^2} \\ \\  = \sqrt{ 1 + 1} \\ \\ = \sqrt{ 2 }

b. 
Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \frac{ 7 }{ 2 } \right)^2 + \left( \frac{ 5 }{ 2 } - 1 \right)^2} \\  \\= \sqrt{ \frac{ 225 }{ 4 } + \frac{ 9 }{ 4 }} \\ \\=  3 \frac{\sqrt{ 26 }}{ 2 }
6 0
3 years ago
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