What is the solution to this equation? a/6-11=25

Name two ordered pairs that are located exactly six units from (2, -3).

Phantasy [73]

Exactly six units from:

Def'n: Add or subtract 6 to either "x" or "y" in (x,y) = (2, -3)
P.S. (BTW, there are many more ways that are a lot harder to find two orders pairs six units from (2, -3). These are only the easiest.)

1. (2, -3 + 6) = (2, 3)
2. (2, -3 - 6) = (2, -9)
3. (2 + 6, -3) = (8, -3)
4. (2 - 6, -3) = (-4, -3)

Pick from these four. :3

5 0

3 years ago

Read 2 more answers

I will mark brainliest!!! Please show work

asambeis [7]

9950x=8650x+250000
Subtract 8650x from both sides
1300x= 250000

3 0

3 years ago

PLEASE HELP

Leto [7]

Answer:

DA = 285.7 m

Step-by-step explanation:

First we need to find the side AB in the triangle ABC, and we can do this using Pythagoras' theorem:

AB^2 = BC^2 + AC^2

AB^2 = 300^2 + 400^2

AB^2 = 25000

AB = 500 m

We can find the angle ABC with the tangent relation:

tangent(ABC) = 400/300 = 4/3

ABC = 53.13°

From triangle ABC, we have:

ABC + BCA + CAB = 180°

53.13 + 90 + CAB = 180

CAB = 36.87°

From triangle DAC, we have:

DAC + ACD + CDA = 180

36.87 + 45 + CDA = 180

CDA = 98.13°

Now to find the side of DA, we can use law of sines in triangle DAC:

DA/sin(DCA) = AC/sin(CDA)

DA/sin(45) = 400/sin(98.13)

DA = 400 * 0.7071 / 0.9899 = 285.7258 m

Rounding to nearest tenth, we have DA = 285.7 m

3 0

3 years ago

A rectangular pool is 20 ft wide and 50 ft long. the pool is surrounded by a walkway. the walkway is the same width all the way

Ratling [72]

50wideis the walkway

8 0

3 years ago

Lee las situaciones y realiza lo siguiente con cada una:

Julli [10]

Answer:

Part 1) see the explanation

Part 2) see the explanation

Part 3) see the explanation

Part 4) see the explanation

Step-by-step explanation:

The question in English is

Read the situations and do the following with each one:

Write down the magnitudes involved

Write which magnitude is the independent variable and which is the dependent variable

It represents the function that describes the situation

SITUATIONS:

1) A machine prints 840 pages every 30 minutes.

2) An elevator takes 6 seconds to go up two floors.

3) A company rents a car at S/ 480 for 12 days.

4) 10 kilograms of papaya cost S/ 35

Part 1) we have

A machine prints 840 pages every 30 minutes

Let

x ----> the time in minutes (represent the variable independent or input value)

y ---> the number of pages that the machine print (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

$k=\frac{y}{x}$

we have

$y=840\ pages\\x=30\ minutes$

substitute

$k=\frac{840}{30}=28\ pages/minute$

The linear equation is

$y=28x$

Part 2) we have

An elevator takes 6 seconds to go up two floors.

Let

x ----> the time in seconds (represent the variable independent or input value)

y ---> the number of floors (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

$k=\frac{y}{x}$

we have

$y=2\ floors\\x=6\ seconds$

substitute

$k=\frac{2}{6}=\frac{1}{3}\ floors/second$

The linear equation is

$y=\frac{1}{3}x$

Part 3) we have

A company rents a car at S/ 480 for 12 days.

Let

x ----> the number of days (represent the variable independent or input value)

y ---> the cost of rent a car (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

$k=\frac{y}{x}$

we have

$y=\$480\\x=12\ days$

substitute

$k=\frac{480}{12}=\$40\ per\ day$

The linear equation is

$y=40x$

Part 4) we have

10 kilograms of papaya cost S/ 35

Let

x ----> the kilograms of papaya (represent the variable independent or input value)

y ---> the cost (represent the dependent variable or output value)

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In this problem

we have a a proportional variation

so

The value of the constant of proportionality is equal to

$k=\frac{y}{x}$

we have

$y=\$35\\x=10\ kg$

substitute

$k=\frac{35}{10}=\$3.5\ per\ kg$

The linear equation is

$y=3.5x$

6 0

3 years ago