You can get all the terms on one side, and then solve for x by any means:

Factor out a -2:

Factor this equation:

I will use the AC method. To use it, first multiply a and c (in ax^2 + bx +c):

Now, look for two numbers that multiply to -12 and add to -11. Obviously these numbers are -12 and 1. (-12*1 = -12 and -12+1 = -11). Now, because of rules, you set it up in a Punnett square:
4x^2 -12x
x -3
Now, we find common factors of the terms in rows:
_x_______-3__
4x| 4x^2 -12x
1 | x -3
So, you can use this to write an equivalent expression to the quadratic given:

Now, we known the factors are (solve for x):
3 and -1/4.
Answer:
I think Leslie Is 20
Step-by-step explanation:
n - 7 = 9
Step-by-step explanation:
so basically just make up a random variable and place it for the "twice a number" then u sovle it as a 2 step equation
Answer:
Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6
Step-by-step explanation:
6 + n x n + 1/2d
6 + n^2 x + 1/2d
Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6
I can give you the first half!
1. D2 - hours worked on monday, 3hrs
2. E2 - money earned on monday, $15
3. D3 - hours worked on tuesday, 3 hrs
4. E3 - money earned on tuesday, $15
5. D4 - hours worked on thursday, 4 hrs
6. E4 - money earned on thursday, $20