The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)
<h3>Further explanation
</h3>
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles γ
- positron particles ₁e⁰
O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same
Reaction

The mass number of the daughter isotope = 15, atomic number = 7
If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)
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To solve this problem, we will use the
Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:

So, the final volume after increasing the pressure would be
2,7 L. That means that volume decreases when the pressure increases
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D , is the correct answer
Answer:
oxidizer: one used to support the combustion of a rocket propellant
word: a single distinct meaningful element of speech or writing
Explanation:
Answer:
a) E = 0.477 V
b) E = 0.502 V
c) 0.02 M = [Ni+2]
d)[Zn+2] = 1.81 M
Explanation:
having the following reactions of each cell:
Zn =⇒ Zn+2 + 2e- +0.76
Ni+2 + 2e- =⇒ Ni -0.25
Zn + Ni+2 ==⇒ Ni + Zn+2 Eo = 0.51
a)
The number of electrons being transferred is 2, therefore n = 2 in the Nernst equation
E = Eo - 0.0592/2*log [Zn+2]/[Ni+2] = 0.51 - 0.0592/2*log[0.13/1.7] = 0.477 V
b)
using the formula above:
E = 0.51 - 0.0296*log [Zn+2]/[Ni+2] = 0.51 - 0.0296*log((0.13+0.5)/(1.7-0.5)) = 0.502 V
c)
using the formula above:
0.45 = 0.51 - 0.0296*log[Zn+2]/[Ni+2]
-0.06/-0.0296 = log[Zn+2]/[Ni+2]
2.02 = log [Zn+] / [Ni+2]
104.71 = [Zn+2] / [Ni+2]
x = change in [Ni+2]
[Ni+2] = 1.70 - x
[Zn+2] = 0.13 + x
0.13 + x/1.70 –x = 104.71
Resolving x:
x = 1.68 M
[Ni+2] = 1.70 - 1.68 = 0.02 M
d)
[Zn+2] = 0.13 + x = 0.13 + 1.68 = 1.81 M