Answer:
-12.5 i think
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
12 divided by -6 is -2, plus 5 is 3
:D
Answer:
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Step-by-step explanation:
Volume of the Cylinder=400 cm³
Volume of a Cylinder=πr²h
Therefore: πr²h=400

Total Surface Area of a Cylinder=2πr²+2πrh
Cost of the materials for the Top and Bottom=0.06 cents per square centimeter
Cost of the materials for the sides=0.03 cents per square centimeter
Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)
C=0.12πr²+0.06πrh
Recall: 
Therefore:



The minimum cost occurs when the derivative of the Cost =0.






r=3.17 cm
Recall that:


h=12.67cm
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Answer:
5/7
Step-by-step explanation:
3-1 2/7
3=21/7 (by multiplying denominator)
1 2/7=16/7 (by multiply 1 and 7. Then add to 2)
21/7 - 16/7 = 5/7