Answer:
cm^3/5
Step-by-step explanation:
STEP 1: m
Simplify ——
60
Equation at the end of step 1: m
((12c • ——) • m) • m
60
STEP 2 :Multiplying exponential expressions : 2.1 m2 multiplied by m1 = m(2 + 1) = m3.
final result is cm^3/5
With g=3
Just replace every g with a 3.
So the equations becomes:
12g·(9÷g)=12(3)·(9÷(3))
This can also be written in the form:

Cancelling out the 3's:
12·9=108
Answer:
Step-by-step explanation:
Prime factorize 121 and 99
121 = 11 * 11
99 = 11 * 3 * 3
Common factor = 11
Complementary angles add up to 90.
Answer:
The range of possible temperatures is the interval [80.5°,95.5°]
Step-by-step explanation:
Let
x -----> possible temperatures for that day.
we know that
The absolute value inequality of the difference of the possible temperatures and the temperature at noon must be less than or equal to 7.5° F
so

Solve the absolute-value inequality
<em>First case (positive case)</em>

Adds 88 both sides


<em>Second case (negative case)</em>

Multiply by -1 both sides

Adds 88 both sides


therefore
The range of possible temperatures is the interval [80.5°,95.5°]