Label the points A,B,C
- A = (1,2)
- B = (4,5)
- C = (8,9)
Let's find the distance from A to B, aka find the length of segment AB.
We use the distance formula.

Segment AB is exactly
units long.
Now let's find the distance from B to C

Segment BC is exactly
units long.
Adding these segments gives

----------------------
Now if A,B,C are collinear then AB+BC should get the length of AC.
AB+BC = AC
Let's calculate the distance from A to C

AC is exactly
units long.
Therefore, we've shown that AB+BC = AC is a true equation.
This proves that A,B,C are collinear.
For more information, check out the segment addition postulate.
2n + 8 ≤ 25 |subtract 8 from both sides
2n ≤ 17 |divide both sides by 2
<u>n ≤ 8.5</u>
Answer:
A
Step-by-step explanation:
X times x is x squared then x times - 2 is - 2x but 4 times x is 4x. So 4x plus - 2x is 2x. Then 4 times - 2 is - 8 put that all together you'll get x^+ 2+2x-8