Question

Suppose a normal distribution has a mean of 266 and a standard deviation of 12. What is P(x ≥ 242)?

Answer 1

Answer:

Step-by-step explanation:

The formula for normal distribution is expressed as

z = (x - u)/s

Where

u = mean

s = standard deviation

From the information given,

u = 266

s = 12

x = 242

We want to determine P(x ≥ 242). This is the probability of x greater than or equal to 242

P(x ≥ 242) = 1 - P(x </=242)

For x = 242,

z = (242 - 266)/12 = -24/12 = -2

Looking at the normal distribution table, the corresponding z score for P(x </= - 2) is 0.02275

P(x ≥ 242) = 1 - 0.02275 = 0.97725