All categories

3 years ago

Explain how to calculate step by step

Physics

1 answer:

Lisa [10]3 years ago

6 0

Answer:

The kinetic friction coefficient is 0.436

Explanation:

In the attached image we can find a sketch of the forces that are acting over the box. And using the second law of movement of Newton we can find two equations which give us the relation between the friction force and the normal force.

The third equation is deducted by the definition of the friction force:

$f=u*N\\where\\u=kinetic friction coefficient\\N =normal force [N]\\$

Then replacing the equation 1 (see image) in the equation 2 we will have the final equation. Then we can clear the value of u (kinetic coeficcient).

The answer is 0.436 and this value is between 0 - 1.

You might be interested in

How much time is needed to produce 900 Joules of work if 120 watts of power is used?

Charra [1.4K]

Answer:

7.5 seconds

Explanation:

because wattsXtime=Joules so 120X__=900. 900 divided by 120= 7.5

6 0

3 years ago

Standing on a bridge, you throw a stone straight upward. The stone hits a stream28.3 m below the point at which you release it2.

Helen [10]

Answer:

MISSING DATA, SPEED AT WHICH IT WAS LAUNCHED OR INITIAL

DISTANCE THAT REACHED UPWARDS

Explanation:

ANYWAY I LEAVE YOU THE LINK, AUÍ AHY MORE INFORMATION ON THE

SUBJECT.

https://gscourses.thinkific.com

4 0

3 years ago

An ideal vapor-compression refrigeration cycle that uses refrigerant-134a as its working fluid maintains a condenser at 800 kpa

AlladinOne [14]

Answer:

P= 30.87 kw

Explanation:

find the solution below

7 0

4 years ago

Read 2 more answers

What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh

Goshia [24]

Answer:

a) $R_s = 0.092$

b) $R_p = 0.085$

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

$R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2$

using snell's law to calculate θ t

$sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}$

$cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}$

a) $R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2$

$R_s = 0.092$

b) $R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2$

$R_p = 0.085$

3 0

3 years ago

Radiant heat makes it impossible to stand close to a hot lava flow. Calculate the rate of heat loss by radiation from 1.00 m^2 o

myrzilka [38]

Answer:

259.274 kW

Explanation:

Given:

Area of the lava, A = 1.00 m²

Temperature of the surrounding, T₁ = 30.0° C = 303 k

Temperature of the lava, T₂ = 1190° C = 1463 K

emissivity, e = 1

Now,

from the Stefan-Boltzmann law of radiation the rate of heat loss is given as,

u = σeA(T₂⁴ - T₁⁴)

where,

u = rate of heat loss

σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/m²∙K⁴

on substituting the respective values, we get

u = 5.67 × 10⁻⁸ × 1 × 1 × (1463⁴ - 303⁴)

u = 259274.957 W

u = 259.274 kW

7 0

3 years ago