6.07 moles
Explanation:
Given parameters:
Number of moles of reacting hydrogen gas = 9.1 moles
Unknown:
Number of moles of ammonia produced = ?
Solution:
Balanced chemical equation:
N₂ + 3H₂ → 2NH₃
We should work from the known to the unknown specie. We known the number of moles of hydrogen gas reacting. We simply relate this to that of the ammonia.
From the reaction:
3 mole of hydrogen gas produced 2 mole of ammonia
9.1 moles of the hydrogen gas will produce: ![\frac{2 x 9.1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%20x%209.1%7D%7B3%7D)
= 6.07 moles
Learn more:
Number of moles brainly.com/question/1841136
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The component of waves must have same frequency and phase.
when the component of waves vibrate at the same rate and attain maximum point at the same time, reinforcement of the waves amplitude occur to cause a constructive interference.However, when the two waves are out of phase where one is at minimum when the other is at maximum a destructive interference happens.
Answer:0.4 m
Explanation:
Given
Maximum displacement A=0.49
The sum of kinetic and elastic potential energy is ![\frac{1}{2}kA^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DkA%5E2)
where k=spring constant
U+K.E.=![\frac{1}{2}kA^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DkA%5E2)
when K.E.=U/2
K.E.=kinetic energy
U=Elastic potential Energy
![\rightarrow \ U+\frac{U}{2}=\frac{1}{2}KA^2\\\rightarrow \ \frac{3U}{2}=\frac{1}{2}KA^2\\\rightarrow \ U=\frac{1}{3}KA^2\\\rightarrow \ \frac{Kx^2}{2}=\frac{1}{3}KA^2\\\\x=\sqrt{\frac{2}{3}}A\\x=0.4\ m](https://tex.z-dn.net/?f=%5Crightarrow%20%5C%20U%2B%5Cfrac%7BU%7D%7B2%7D%3D%5Cfrac%7B1%7D%7B2%7DKA%5E2%5C%5C%5Crightarrow%20%5C%20%5Cfrac%7B3U%7D%7B2%7D%3D%5Cfrac%7B1%7D%7B2%7DKA%5E2%5C%5C%5Crightarrow%20%5C%20U%3D%5Cfrac%7B1%7D%7B3%7DKA%5E2%5C%5C%5Crightarrow%20%5C%20%5Cfrac%7BKx%5E2%7D%7B2%7D%3D%5Cfrac%7B1%7D%7B3%7DKA%5E2%5C%5C%5C%5Cx%3D%5Csqrt%7B%5Cfrac%7B2%7D%7B3%7D%7DA%5C%5Cx%3D0.4%5C%20m)
0.0605J is your answer. Use the formula KE=1/2mv^2