Answer:
1038.96 kPa
Explanation:
We’ll use the ideal gas law; P1V1/T1 = P2V2/T2
P1*14.8/75.5 = 101.3*16.5/70.2
P1 = (101.3 * 16.5 * 75.5) / (70.2 *14.8)
P1 = 1038.96
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<span>According to Georgia Perimeter College, </span>tap water<span> is not </span>heterogeneous.Heterogeneous mixtures<span> have at least two substances, and viewers can see what is in it. </span>Tap water<span> is </span>homogeneous<span>, as </span>homogeneous mixtures<span> have at least two substances in them, but viewers cannot see them.</span>
Answer:
![Ca^{2+} and Co^{2+}](https://tex.z-dn.net/?f=Ca%5E%7B2%2B%7D%20%20and%20%20Co%5E%7B2%2B%7D)
Explanation:
Given:
A solution contains one or more of the following ions such as Ag,
and ![Co_2](https://tex.z-dn.net/?f=Co_2)
Here the Lithium bromide is added to the solution and no precipitate forms
Solution:
Since with LiBr no precipitation takes place therefore Ag+ is absent
Here on adding
to it precipitation takes place.
Precipitate is as follows,
![Ca^{2+}(aq)+SO_4^2^-(aq)----->CASO_4(s)](https://tex.z-dn.net/?f=Ca%5E%7B2%2B%7D%28aq%29%2BSO_4%5E2%5E-%28aq%29-----%3ECASO_4%28s%29)
Thus,
is present
When
is added again precipitation takes place.
Therefore the reaction is as follows,
![Co^2^+(aq)+PO_4^3^-(aq)------>Co_3(PO_4)_2(s)](https://tex.z-dn.net/?f=Co%5E2%5E%2B%28aq%29%2BPO_4%5E3%5E-%28aq%29------%3ECo_3%28PO_4%29_2%28s%29)
Therefore,
are present in the solution