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jeka94
3 years ago
15

A motorcycle travels 823 meters in 20 seconds. What is the average speed? _____ m/s

Chemistry
1 answer:
docker41 [41]3 years ago
4 0
41 meters per second
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What mass of chlorine gas is contained in a 10.0 L tank at 31.0° C and 3.50 atm?
jeyben [28]
You need to use the ideal gas law (PV=nRT) and solve for n. ((3.50atm•10.0L)/(0.0821(L•atm/mol•K)•304K) = n = 1.40 moles. 1 mole of Cl2 = 70.9 gm/mole. The mass would be 99.43 gm
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3 years ago
In a chemical reaction, the mass of the products ____.
Pani-rosa [81]
In a chemical reaction, the mass of the products<span> is less than the mass of the reactants.
the first step in most stoichiometry problems is to <span>convert given quantities to moles.

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5 0
3 years ago
Read 2 more answers
If a frog has 26 chromosomes in its body cells, then it must have ______ cells in its gametes
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Answer:

sxfdcghbjkml

Explanation:

4 0
2 years ago
The electronegativity of the element affects all of the following except a- type of bond it forms with other elements b- the boi
seraphim [82]

The electronegativity of the element affects the ability of its compounds to dissolve in different solvents.

<h3>What is the meaning of electronegativity?</h3>

Electronegativity is a measure of an atom's ability to attract shared electrons to itself.

Polar bonds have a positive and negative side to them, and therefore can attract water dipoles and dissolve in water.

If the polarities of the solvent and solute match (both are polar or both are nonpolar), then the solute will probably dissolve.

If the polarities of the solvent and solute are different (one is polar, one is nonpolar), the solute probably won't dissolve.

Hence, option D is correct.

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6 0
2 years ago
You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans
OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

<u>Vi = 0.145 l or 145 ml</u>

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

4 0
3 years ago
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