Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)
The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)
ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa
Answer:
hmm lemme think bur it will take a while
Answer:
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Answer:
4 enzymes responsible for digestion:
1. Salivary amylase ---- substrate: Starch ---- end-product: Maltose
2. Lipase ---- substrate: Lipids (fats and oils) ---- end-product: Fatty acids and glycerol
3. Maltase ---- substrate: Maltose ---- end-product: Glucose
4. Protease ---- substrate: Protein ---- end-product: Amino acids
Field or discipline
hope it helped
