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daser333 [38]
3 years ago
15

[23-3] + [6x9 how to solve it

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:74 is the answer and you would use P.E.M.D.A.S to solve

Step-by-step explanation:

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2 years ago
Rosita earns money by walking dogs after school and on weekends.She walks Madeline every other day,buddy every fourth day,and er
leonid [27]

On 12th day Rosita will walk all three dogs

<em><u>Solution:</u></em>

Given that Rosita earns money by walking dogs after school and on weekends

She walks Madeline every other day,buddy every fourth day,and ernie every third day

Today she walked all three dogs

<em><u>To find: the day when she walked all three dogs</u></em>

From given question,

Madeline is walked every other day means every two days:  2

Buddy is walked every fourth day:  4

Ernie is walked every third day:  3

To find the day when she walked all three dogs, we have to find the least common multiple (LCM) of 2, 4, 3

<em><u>L.C.M of 2, 4, 3:</u></em>

List all prime factors for each number

Prime Factorization of 2 shows:

2 is prime  => 2^1

Prime Factorization of 3 shows:

3 is prime  => 3^1

Prime Factorization of 4 is:

2 \times 2 = 2^2

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 3

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 3 = 12

Thus on 12th day Rosita will walk all three dogs

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3 years ago
Cancel the common factor of the numerator and the denominator and write specified expression
lisabon 2012 [21]

Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

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So if we take 29.5 to be the 100%, what is 10.03 in percentage?

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