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g100num [7]
2 years ago
15

What is the slope and equation of the graph?

Mathematics
1 answer:
jasenka [17]2 years ago
3 0

Answer:

Looks like the slope is -(1/2) and the equation is y= -(1/2)x + 1

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Write a equation of a hyperbola given the foci and the asymptotes
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Solution:

The standard equation of a hyperbola is expressed as

\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}

The asymptote of n hyperbola is expressed as

y=\pm\frac{a}{b}(x-h)+k

Given that the asymptotes are

y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x

This implies that

a=3,\text{ and b=4}

To evaluate the value of h and k,

undefined

3 0
1 year ago
Please help with my geometry
erma4kov [3.2K]
25 = hypothenuse
14 = opposite
Use SOHCAHTOA
Give O and H, you can use sin
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Round to hundreds
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3 years ago
After school Rayah skateboards at a constant rate from her house to her friend's house 1.8 miles away. It takes her 12 minutes t
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Answer:

Step-by-step explanation:

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