Answer:
<em>− 2sin(b) / cos(2b)</em>
Step-by-step explanation:
DIFFERENTIATE W.R.T. B is a different method entirely
We simply add together the numerators and set with 2cos
then keep this number and add to sinb and square it.
then repeat initial 2 + cosb ^2 but instead of multiplying its add.
Then set the whole division to -sin (2b) squared then +1
<em> − 2cos(b)(3(sin(b))^2+(cos(b))^2) / −(sin(2b)) ^2 +1 </em>
To answer this problem, one way is to use the calculator and add directly the two numbers and get the average between the two. The answer is 25/77. We can also get this number by getting the LCM of the denominators which is 77. 2/7 is equal to 22/77 while 4/11 is equal to 28/77. 0.5*(22 +28) is equal to 25. Hence the answer is 25/77.
Answer:
(x, g(x)) = {(-2, -2), (0, 0), (2, 2), (4, -3), (6, -3)}
Step-by-step explanation:
The first three values of x in the table are all less than or equal to 2, so the first part of the function definition applies. The y-value is equal to the x-value. The ordered pairs are ...
(-2, -2), (0, 0), (2, 2)
The last two values of x in the table are more than 2, so the last part of the function definition applies. For those values of x, the y-value is -3. The ordered pairs are ...
(4, -3), (6, -3)
Answer:
Step-by-step explanation:
If Samantha's earnings continue to increase at the same rate, this means that her earning is increasing arithmetically.
If she earned $550 in the first day, we can say the first term is $550
If she earned $750 on the third day, we can say the third term is $750
For us to know by how much her money is increasing, we need to find the common difference d formed by the sequence
550, x , 750
T1 = 550
T2 = x
T3 = 750
Common difference d = T2-T1 = T3-T2
x - 550 = 750 - x = d
Let's calculate the second term first i.e x
Since x - 550 = 750 - x = d
x - 550 = 750 - x
Collect like terms
x+x = 750+550
2x = 1300
x = 1300/2
x = 650
d = T2-T1
d = x - T1
d = 650-550
d = 100
Hence her money keeps increasing by $100 each day
