X1 + X2 + X3 <27 for all Xi> 0
X1 + X2 + X3 <27 for all Xi> 0, X2 >/ 5
There are three steps:<span>Rearrange the equation so "y" is on the left and everything else on the right.Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)<span>Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).</span></span>
Let x be the number of boys, the number of girls will be 200-x
Number of boys with blue eyes x/3
Number of girls with blue eyes (200-x)/4
ll blue eyes ==> x/3 + (200-x)/4 = 57
Reduce to same denominator & solve for x
(4x + 600 - 3x)/12 = 681/12
x=81, the total number of boys & girls200-81 119
I can help you if you still!!!
Answer:
2b+t/2=a
Step-by-step explanation:
3a + 4b = 5a-t
-3a -3a
4b = 2a - t
+t +t
4b + t = 2a
/2 /2
2b+t/2=a
