<h2>
Hey There!</h2><h2>_____________________________________</h2><h2>
Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>
Angle of projection = θ(theta) =
Initial Velocity = =
Acceleration due to gravity = g = 9.8 m/s^2
Vertical Velocity = = ?
Horizontal Velocity = = ?
Range of the Shell = R = ?
Maximum Height = H = ?
<h2>_____________________________________</h2><h3>SOLUTION:</h3>
Vertical Velocity is given by,
θ
Horizontal Velocity is given by,
θ
Range is given by,
R = Sin2θ
Horizontal Velocity is given by,
<h2>
_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>
To solve this problem we will begin by applying the given relations of density in terms of mass and volume, and from this last value we will take its geometric measurement for a sphere (Approximation of a planet) From there we will find the radius of the planet. Finally we will make a comparison between the radius of the new planet and the radius of the earth to understand its proportion.
Defining the Volume variables we have to
Here
V= Volume
m = mass
=Density
For a spherical object the Volume is
PART A)
Equation we have
In this case the mass of new planet is 5.5times the mass of Earth,
Then,
The mass of the Earth is kg and the density is ,
Replacing we have that,
Therefore the radius of this new planet is
PART B) The value of radius of the Earth is
Then the relation between them is
Therefore the radius of the new planet in terms of radius of the Earth is
Answer:
Potential difference across resistor will be 87.66 volt
Explanation:
We have given number of electrons
Charge on one electron
So total charge
Time is given t = 5 min
1 minute = 60 sec
So 5 minute = 5×60 = 300 sec
So current
Resistance is given R = 40 ohm
Sp from ohm's law potential difference across resistor v = iR = 2.1866×40 = 87.466 volt
Answer:
I_total = L² (m + M / 3)
Explanation:
The moment of inertia is defined by
I = ∫ r² dm
It is appreciated that it is a scalar quantity, for which it is additive, in this case the system is formed by two bodies and the moment of inertia must be the sum of each moment of inertia with respect to the same axis of rotation.
The moment of inertia of a bar with respect to an axis that passes through ends is
I_bar = 1/3 M L²
The moment of inertia of a particle is
I_part = m x²
We have to assume the point where the particle sticks to the bar, suppose it sticks to the end
x = L
Total moment of inertia is the sum of these two moments of inertia
I_total = I_bar + I_particule
I_total = 1/3 M L² + m L²
I_total = L² (m + M / 3)