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liubo4ka [24]
3 years ago
12

I need help with these questions :(see image )​

Physics
1 answer:
lara31 [8.8K]3 years ago
7 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>

Angle of projection = θ(theta) = 30^0

Initial Velocity = V_0 = 2x10^3

Acceleration due to gravity = g = 9.8 m/s^2

Vertical Velocity = V_Y = ?

Horizontal Velocity = V_X = ?

Range of the Shell = R = ?

Maximum Height = H = ?

<h2>_____________________________________</h2><h3>SOLUTION:</h3>

Vertical Velocity is given by,

                                 V_Y = V_0Cosθ

                                 V_Y = (2x10^3)xCos(30)

                                 V_Y = (2x10)^3x(0.866)\\\\V_Y = 1732.05 \frac{m}{s}

Horizontal Velocity is given by,

                                 V_X = V_0Sinθ

                                 V_X = (2x10^3)xSin(30)\\\\V_X = (2000)x(0.5)\\\\V_X = 1000\frac{m}{s}

Range is given by,

                                R =   \frac{V_0^2}{g}  Sin2θ        

                                R = \frac{(2x10^3)^2}{10} x Sin(60)\\\\R = \frac{4x10^6}{10} x 0.866\\\\R= (4x10^5) x 0.866\\\\R = 346410.16 m                    

Horizontal Velocity is given by,

<h2>                                 H = \frac{V_0^2Sin^2(theta)}{2g}\\\\\\H= \frac{(2x10^3)^2xSin(30)^2}{2x10}\\\\\\H= \frac{(4x10^6)x(0.25)}{20} \\\\H = 50000 m                             _____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>
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