Answer:
C. 5.6 × 10^11 N/C
Explanation:
The electric field
at a distance
from a charge
is given by

where
is the coulomb's constant.
Now, in our case

;
therefore,


which is choice C from the options given<em> (at least it resembles it).</em>
Answer:
a) 200A
b) 10.2V
c) 2.04kW
d)
I=80A
V=4.08V
P=0.326kW
Explanation:
Here we have a circuit of one power source and two resistors in series, the first question is asking for the current, so according to Ohm's Law:

Where R is the equivalent resistance of the resistors in series
![R=0.0510+0.0090=0.0600[ohm]](https://tex.z-dn.net/?f=R%3D0.0510%2B0.0090%3D0.0600%5Bohm%5D)

To calculate the voltage dropped by the motor we have to apply the voltage divider rule:

The power dissipated supplied to the motor is given by:

now solving adding a 0.0900 ohm resistor:



Answer:N=322.53 rpm
Explanation:
Given
Linear velocity (v)=1.25 m/s
Position from center is 3.7 cm
we know



and 


N=322.53 rpm
21.75 Miles Per Hour
I got this by multiplying 7.25(3) because I know 20 minutes is 1/3 of 1 he