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Ivanshal [37]
4 years ago
15

If 4.1 × 1021 electrons pass through a 40 Ω resistor in 5 min, what is the potential difference across the resistor? The fundame

ntal charge is 1.602 × 10−19 C . Answer in units of V
Physics
1 answer:
nydimaria [60]4 years ago
7 0

Answer:

Potential difference across resistor will be 87.66 volt

Explanation:

We have given number of electrons n=4.1\times 10^{21}

Charge on one electron e=1.6\times 10^{-19}C

So total charge Q=4.1\times 10^{21}\times 1.6\times 10^{-19}=656C

Time is given t = 5 min

1 minute = 60 sec

So 5 minute = 5×60 = 300 sec

So current i=\frac{Q}{t}=\frac{656}{300}=2.1866A

Resistance is given R = 40 ohm

Sp from ohm's law potential difference across resistor v = iR = 2.1866×40 = 87.466 volt

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All electromagnetic waves travel at

299,792,458 meters per second

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7 0
4 years ago
What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 7400 N
bezimeni [28]

Answer: a = 1.32 * 10^18m/s² due north

Explanation: The magnitude of the force required to move the electron is given as

F = ma

The force exerted on the charge by the electric field of intensity (E) is given by

F = Eq

Thus

Eq = ma

a = E * q/ m

Where a = acceleration of charge

E = strength of electric field = 7400N/c

q = magnitude of electronic charge = 1.609 * 10^-6c

m = mass of an electronic charge = 9.109 * 10^-31kg

a = 7400 * 1.609 * 10^-16/ 9.109 * 10^-31

a = 11906.6 * 10^-16 / 9.019 * 10^-31

a = 1.19 * 10^-12 / 9.019 * 10^-31

a = 0.132 * 10^19

a = 1.32 * 10^18m/s²

As stated in the question, the direction of the electric field is due north hence, the direction of it force will also be north thus making the electron experience a force due north ( according to Newton second law of motion)

5 0
3 years ago
What is the angle θ between vectors A⃗ and B⃗ if A⃗ =4ı^−4ȷ^ and B⃗ =−5ı^+7ȷ^?
ololo11 [35]

The characteristics of the scalar product allows to find the angle between the two vectors is:

  • The angle θ = 170º

The scalar product is the product between two vectors whose result is a scalar.

            A . B = |A|  |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

            i.i = j.j = 1

            i.j = 0

            A . B = (4 i - 4j). * -5 i + 7j)

            A . B = - 4 5 - 4 7

            A. B = -48

We look for the modulus of each vector.

           |A| = \sqrt{x^2 +y^2 }

           |A| = \sqrt{4^2 + 4^2}  

           |A| = 4 √2

          |B| = \sqrt{5^2 +7^2}

          |B| = 8.60

We substitute.

            -48 = 4√2  8.60  cos θ

            -48 = 48.66 cos θ

            θ = cos⁻¹   \frac{-48}{48.664}  

            θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

  • the angle θ = 170º

Learn more about the scalar product here:  brainly.com/question/1550649

8 0
3 years ago
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B.. It can easily be transformed from high voltages to low voltages.
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Which of the following is true about "natural" steroids?
crimeas [40]

Answer:

The answer is C

Explanation:

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4 years ago
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