Answer:
2 amps
Explanation:
Given data
Power = 460W
voltage= 230V
Required
The amperage/ current of the fuse
Recall P= IV
I= P/V
I= 460/230
I=2 amps
Hence the current of the fuse is 2 amps
Answer:
a) S = v₀² / 4 g sin θ
Explanation:
Let's apply Newton's second law, let's take a coordinate system with an axis parallel to the plane and the other perpendicular, in this case the only force that we have to decompose the weight (W)
Wx = W sin θ
Wy = W cos θ
First case. Body slides down
X axis
Wx-fr = 0
Axis y
N -Wy = 0
N = Wy
fr = Wx = W sint θ
Miu N = W sint θ
Miu W cos θ = Wsin θ
Miu = tan θ
Second case. Body raises the plane
X axis
Wx + Fr = m a
Axis y
N-Wy = 0
let's find the acceleration of the body going up
a = (Wx + fr) / m
fr = μ N = μ Wy
fr = μ mg cos θ
a = (mg sin θ + μ mg cos θ) / m
a = g (sin θ + μ cos θ)
a = g (sin θ + tan θ cos θ)
a = g (sin θ + sin θ)
a = g 2 sin 2
With the kinematic equation we find the distance that goes up, at the highest point the zero speed (vf = 0)
Vf² = v₀² - 2 a t S
0 = v₀² -2a S
S = v₀² / 2 a
S = v₀² / 2 (g 2sin θ)
S = v₀² / 4 g sin θ
b) in this case the block tries to slide down whereby the friction force opposes this movement
Wx- fr =, m a
mg sin θ - μ mg cos θ = m a
g (sin θ - μ cos θ) = a
a = g 2 sin θ
so that the body slides depends on the angle T for angles close to zero the body does not slide
Answer:
While the Applied Force (force exerted) is decreasing, the velocity is decreasing
Explanation:
From Newton's second law of motion, which states that the rate of change of linear momentum is directly proportional to the applied force, and takes place in the direction of the applied force.
Momentum (P) = MV
Thus, F ∝ MV/t
where;
F is the applied force
M is the mass of the object
V is the velocity of the object
From the equation above, force is directly proportional to the velocity of the refrigerator (F∝V). That is, as the applied force is decreasing, the velocity is decreasing and vice versa.
Therefore, while the Applied Force (force exerted) is decreasing, the velocity is decreasing.