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m_a_m_a [10]
3 years ago
11

One of the ways that scientists determine the distance between Earth and other objects in space is to send light waves toward an

object and measure how long it takes for the waves to bounce back. If a scientist sends light waves to four different objects in space, which of the following will take the longest to bounce the wave back to Earth?
a star in the Milky Way Galaxy


a star in the Andromeda Galaxy


a planet in Earth's Solar System


a planet in another star system within the Milky Way Galaxy
Physics
1 answer:
Ahat [919]3 years ago
7 0

Answer:

a star in andromeda

Explanation:

all of the other objects are in the milkyway (where we are) and the andromeda galaxy is 2 million light years away from us

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Justify why sound waves need a medium to propagate with example??
Lana71 [14]

Answer:

Sound needs a material medium for their propagation like solid, liquid or gas to travel because the molecules of solid, liquid and gases carry sound waves from one point to another. Sound cannot progress through the vacuum because the vacuum has no molecules which can vibrate and carry the sound waves.

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3 years ago
David is driving a steady 30 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2
dangina [55]
A. 441 m B: 46.0 m/s
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3 years ago
PLS HELP ME
NeTakaya
The answer is true...
4 0
3 years ago
A rod of length L and mass M has a nonuniform mass distribution. The linear mass density (mass per length) is λ=cx2, where x is
grigory [225]

Answer:

Explanation:

λ=c x²

c = λ / x²

λ is mass / length

so its dimensional formula is ML⁻¹

x is length so its dimensional formula is L

c = λ / x²

= ML⁻¹ / L²

= ML⁻³

B )

We shall find out the mass of the rod with the help of given expression of mass per unit length and equate it with given mass that is M

The mass in the rod is symmetrically distributed on both side of middle point.

we consider a small strip of rod of length dx at x distance away from middle point

its mass dm = λdx = cx² dx

By integrating it from -L to +L we can calculate mass of whole rod , that is

M = ∫cx² dx

= [c x³ / 3] from -L/2 to +L/2

= c/3 [ L³/8 + L³/8]

M = c L³/12

c = 12 M L⁻³

C ) Moment of inertia of rod

∫dmx²

= ∫λdxx²

= ∫cx²dxx²

= ∫cx⁴dx

= c x⁵ / 5 from - L/2 to L/2

= c / 5 ( L⁵/ 32 +L⁵/ 32)

= (2c / 160)L⁵

= (c / 80) L⁵

= (12 M L⁻³/80)L⁵

= 3/20 ML²

=

=

4 0
3 years ago
A small block of mass m on a horizontal frictionless surface is attached to a horizontal spring that has force constant k. The b
Rashid [163]

Answer:

v_{max} = |d|\cdot \sqrt{\frac{k}{m} }

Explanation:

The maximum speed of the block occurs when spring has no deformation, that is, there is no elastic potential energy, which can be remarked from appropriate application of the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot d^{2} = \frac{1}{2}\cdot m \cdot v^{2}

k \cdot d^{2} = m\cdot v^{2}

v_{max} = |d|\cdot \sqrt{\frac{k}{m} }

5 0
3 years ago
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