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4 years ago

How do you calculate the following: Final Velocity? Acceleration? and Force?

2 answers:

6 0

Wait like the equations, or is there an actual question?

Equations are

Final velocity (Vf) = Initial velocity (Vi) + Acceleration (a) x Time (t)
Acceleration (a) = (Final velocity [Vf] - initial velocity [Vi]) divided by Time (t)
Force (f) = Mass (m) x Acceleration (a)

(Short version)

Vf = Vi + a(t)
a = (Vf - Vi) divided by t
F = m x a

DedPeter [7]4 years ago

3 0

V = u + at. Where v = Final Velocity in m/s. u = initial velocity in m/s, a = acceleration m/s2, t = time in s.

a = (v -u) / t.

F = ma, Where F = force in Newton, m = mass in Kg.

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A water rocket has a mass of 0.8kg and is launched in a school playground with an inital upwards force of 12newtons. what is the

Darina [25.2K]

Weight = (mass) x (gravity).
It always acts downward.

On Earth, the acceleration of gravity is 9.807 m/s².
On the Moon, the acceleration of gravity is 1.623 m/s².

On Earth, the rocket's weight is (0.8kg) x (9.8 m/s²) = 7.84 newtons

On the Moon, the rocket's weight is (0.8kg) x (1.62 m/s²) = 1.3 newtons

The force of the rocket engine acts upward.
Its magnitude is 12 newtons. (From the burning chemicals.
Doesn't depend on local gravity. Same force everywhere.)

Now we have all the data we need to mash together and calculate the
answers to the question. You might choose a different method, but the
machine that I have selected to do the mashing with is Newton's 2nd law
of motion:

   Net Force = (mass) x (acceleration).

Since the question is asking for acceleration, let's first solve Newton's law
for it. Divide each side by (mass) and we have

   Acceleration = (net force) / (mass) .

On Earth, the forces on the rocket are

      (weight of 7.84 N down) + (blast of 12 N up) = 4.16 newtons UP (net)

   Acceleration = (4.16 newtons UP) / (0.8 kg) = 5.2 m/s² UP .

On the moon, the forces on the rocket are

   (weight of 1.3 N down) + (blast of 12 N up) = 10.7 newtons UP (net)

   Acceleration = (10.7 newtons UP) / (0.8 kg) = 13.375 m/s² UP

7 0

3 years ago

An automobile tire having a temperature of 6.7 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 25 lb/in2 . What

OlgaM077 [116]

Answer: The gauge pressure in the tire when its temperature rises to 33◦C will be 28.7 lb/in2

Explanation: Please see the attachments below

3 0

3 years ago

A 16.0 m long, thin, uniform metal rod slides north at a speed of 21.0 m/s. The length of the rod maintains an east-west orienta

Gekata [30.6K]

Answer:

14.112 mV

Explanation:

L = 16 m, v = 21 m/s, B = 42 μ T = 42 x 10^-6 T

The formula for the induced emf is given by

e = B x v x L

e = 42 x 10^-6 x 21 x 16 = 14.112 x 10^-3 V = 14.112 mV

Thus, the induce emf is 14.112 mV.

4 0

3 years ago

the pilot of a new stealth helicopter which has a mass of 15000 kg and was traveling 180 m / s accelerated to 250 m / s in six s

MariettaO [177]

Answer:

pf = 3750000 kg.m/s

F = 175000 N

Explanation:

Constant Acceleration

An object moves with constant acceleration if its velocity changes uniformly in time.

If we call vo to the initial speed, vf the final speed, and t the time, then the acceleration is calculated as:

$\displaystyle a=\frac{v_f-v_o}{t}$

The new stealth helicopter was traveling at vo=180m/s and changed to vf=250 m/s in t=6 seconds, thus the acceleration was:

$\displaystyle a=\frac{250-180}{6}$

$a=11.67~m/s^2$

Please note this number is shown rounded to the nearest hundredth, but it was stored in the calculator's memory with full precision. This fact affects the next calculation as will be noted below.

The acceleration must be produced for some net force that can be calculated by:

F = m.a

Where m=15000 Kg is the mass of the helicopter. Thus:

F = 15000 * 11.67

F = 175000 N

The above product would lead to the inaccurate result of 175050 if the acceleration would have not used with its full representation in the calculator's memory.

The momentum of an object of mass m and velocity v is:

p = m. v

The final momentum of the helicopter is:

pf = m.vf = 15000*250 m/s

pf = 3750000 kg.m/s

Note: When performing calculations over intermediate results, it's important to keep them as accurate as possible to preserve the accuracy of the final result.

6 0

3 years ago

A ledge on a building is 20 m above the ground. A taut rope attached to a 4.0 kg can of paint sitting on the ledge passes up ove

Andrews [41]

Answer:

t = 5.4 s

Explanation:

from the question we are given :

height (s) = 20 m

mass of paint (Mp) = 4 kg

mass of nails (Mn) = 3 kg

acceleration due to gravity (g) = 9.8 m/s^{2}

The net force accelerating the can of paint should be equal to the difference in weight of the can of paint and the can of nails.

weight of nails = mass of nails x g = 3 x 9.8 = 29.4 N

weight of paint = mass nails x g = 4 x 9.8 = 39.2 N

net force = 39.2 - 29.4 = 9.8 N

net force = total mass x acceleration

9.8 = (3 +4) x a

a = 1.4 m/s^{2}

from S = Ut + 0.5at^{2} we can get the time the carpenter has to catch the nails

where U is the initial velocity and is 0 since the can was initially at

rest

20 = (0 x t) + (0.5 x 1.4 x t^{2})

20 = 0.7 x t^{2}

t^{2} = 28.6

t = 5.4 s

8 0

3 years ago