$\left(\frac{(x^4y^{-2})^4}{(2x^2)^2\cdot2x^0y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{4x^4\cdot2y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{8x^4y^3}\right)^2=\\
\left(\frac{x^{12}y^{-11}}{8}\right)^2=\\
\frac{x^{24}y^{-22}}{64}$

3 0

3 years ago

PLEASE ANSWER

Natasha2012 [34]

Answer:

Step-by-step explanation:

5 0

2 years ago

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Help with Mathematics please. Thanks

jekas [21]

The answer would be your last option, D, 168 cm sq

Hope this helped!

8 0

3 years ago

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