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Bond [772]
3 years ago
6

The quadratic x^2-6x+66 can be written in the form (x+b)^2+c, where b and c are constants. What is b+c?

Mathematics
1 answer:
jekas [21]3 years ago
7 0
Complete the square!

x^2-6x+66
=((x-3)^2-9) + 66
=(x-3)^2+57
so
b=-3, c=57
b+c=-3+57=54

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Alex17521 [72]

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<span>
The factorized form of 4a^2c^2 - (a^2-b^2+c^2)^2 is (b - a + c)(b + a - c)(a + b + c)(a - b + c)</span>

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Step-by-step explanation:

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