What is the value of x in the equation 4x+8y=40 when y=0.8

Mathematics

2 answers:

jolli1 [7]3 years ago

4 0

you plug in the y .8 to the 8 that is 6.4

them you subtract 40 by 6.4 that is 33.6

then you divide that by 4 is 8.4

GREYUIT [131]3 years ago

3 0

Substitute in 0.8 for y.

$4x+8y=40 \\ \\ 4x + 8(0.8) = 40 \\ \\ 4x + 6.5 = 40 \\ \\ 4x = 40 - 6.4 \\ \\ 4x = 33.6 \\ \\ x = 8.4 \\ \\$

The final result is: x = 8.4.

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$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill$

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