Answer:
$65,300
Explanation:
Ivanhoe's income tax expense = deferred tax liability 2021 - deferred tax liability 2020 + current tax expense 2020 = $42,800 - $26,800 + $49,300 = $65,300
A deferred tax liability occurs when a corporation's income statement shows a certain amount following US GAAP, but the tax rules used by the IRS determine a different amount.
Answer:
Amount to be borrowed $18,040
Explanation:
The computation of the amount that should be borrowed is given below:
Opening cash balance $29,500
Add Cash Receipts $98,000
Less Cash Disbursements -$122,540
Balance before adjustment $4,960
Desired ending cash balance $23,000
Amount to be borrowed $18,040
Answer:
She lost $754.05.
Explanation:
Giving the following information:
Liz Mulig earns 52,000 per year as a philosophy professor. She receives a raise of 2.5% in a year in which CPI increases by 3.8%.
<u>The rise in her salary allows her to increase her purchasing power. On the contrary, inflation decreases purchasing power. We need to calculate the differences between both effects and determine whether she can buy more or less.</u>
<u></u>
Increase in salary= 52,000*1.025= $53,300
Inflation effect= 52,000/(1-0.038)= $54,054.05
To maintain her purchasing power, now, she needs to earn $54,054.05.
She lost $754.05.
<span>n/2 = average number of items to search.
Or more precisely (n+1)/2
I could just assert that the answer is n/2, but instead I'll prove it. Since each item has the same probability of being searched for, I'll simulate performing n searches on a list of n items and then calculate the average length of the searches. So I'll have 1 search with a length of 1, another search looks at 2, next search is 3, and so forth and so on until I have the nth search looking at n items. The total number of items looked at for those n searches will be:
1 + 2 + 3 + 4 + ... + n
Now if you want to find the sum of numbers from 1 to n, the formula turns out to be n(n+1)/2
And of course, the average will be that sum divided by n. So we have (n(n+1)/2)/n = (n+1)/2 = n/2 + 1/2
Most people will ignore that constant figure of 1/2 and simply say that if you're doing a linear search of an unsorted list, on average, you'll have to look at half of the list.</span>
