Question

Sopve each quadratic equation 1) 3x^2+6x+6=0

Answer 1

Hello from MrBillDoesMath!

Answer:  There is no real solution to equation 1)

(It's implied that other equations are involved in this problem The other equations were not provided by the author)

Discussion:

Divide each side of the equation by 3. This gives

x^2 + 2x + 2 = 0

or

(x^2 + 2x + 1) + 1 = 0

or

(x+1)^2 +1 = 0

or

(x+1)^2 = -1

But any number squared is positive so the last equation has NO solution

Thank you,

MrB