<h3>
Answer:</h3>
B. (5, -2)
<h3>
Step-by-step explanation:</h3>
Try the points in the inequalities and see what works. Here, we evaluate the point in the first inequality, and if that works, then the second inequality.
A. 2 ≤ -(-5) -5 . . . ⇒ . . . 2 ≤ 0 . . . false
B. -2 ≤ 5 -5 . . . true
... -2 ≥ -(5) -4 . . . true . . . . . . selection B is a viable choice
C. we know from A that the first inequality will be satisfied
... -2 ≥ -(-5) -4 . . . ⇒ . . . -2 ≥ 1 . . . false
D. 2 ≤ 5 -5 . . . . false
We know that
A difference of two perfect squares (A² - B²) <span>can be factored into </span><span> (A+B) • (A-B)
</span> then
x ^4-4--------> (x²-2)*(x²+2)
(x²-2)--------> (x-√2)*(x+√2)
x1=+√2
x2=-√2
the other term
(x²+2)=0-> x²=-2-------------- x=(+-)√-2
i <span> is called the </span><span>imaginary unit. </span><span>It satisfies </span><span> i</span>²<span> =-1
</span><span>Both </span><span> i </span><span> and </span><span> -i </span><span> are the square roots of </span><span> -1
</span><span>√<span> -2 </span></span> =√<span> -1• 2 </span><span> = </span>√ -1 •√<span> 2 </span> =i • <span> √<span> 2 </span></span>
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x3= 0 + √2<span> <span>i
</span></span>x4= 0 - √2<span> i </span>
the answer is
the values of x are
x1=+√2
x2=-√2
x3= 0 + √2 i
x4= 0 - √2 i
Depending on the first term, the sequences
would work.
If the sequence began at 6,
If the sequence began at 1,
If the sequence began at 3,
Answer: (-2,1)
Step-by-step explanation:
The point (1,2) is in quadrant 1.
When rotated 90 degrees counter clockwise, it moves to quadrant 2.
The new point becomes (-2,1)
Answer:
The P-value is 0.0234.
Step-by-step explanation:
We are given that a statistics practitioner calculated the mean and the standard deviation from a sample of 400. They are x = 98 and s = 20.
Let = population mean.
So, Null Hypothesis, : = 100 {means that the population mean is equal to 100}
Alternate Hypothesis, : > 100 {means that the population mean is more than 100}
The test statistics that will be used here is One-sample t-test statistics because we're yet to know about the population standard deviation;
T.S. = ~
where, = sample mean = 98
s = sample standard deviation = 20
n = sample size = 400
So, the test statistics = ~
= -2
The value of t-test statistics is -2.
Now, the P-value of the test statistics is given by;
P( < -2) = 0.0234 {using the t-table}
