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Savatey [412]
4 years ago
13

A square has a side length of 2inches. What is the area? What isthe perimeter?​

Mathematics
2 answers:
nlexa [21]4 years ago
8 0

Answer:

Area= 4       2x2

Perimeter=8          2+2+2+

nordsb [41]4 years ago
7 0

Perimeter {4+4+4+4}

=16cm

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The weight of Lyle’s dog increased from 29.7 pounds to 48.9 pounds in an 8-month period. What was the dog’s average weight incre
krok68 [10]
First subtract the weight the dog weighs now to the weight he was:

48.9
- 29.7
------------
19.2

Then take the number you got which is the weight the dog gain in total, and divide it by the months the dog gained weight to get the average weight gained each month:


19.2/8 = 2.4

The average weight gain each month was 2.4 pounds.

Hope this helped you!
6 0
3 years ago
Regis leans a 10-foot ladder against a wall. The base of the ladder makes a 65 angle with the ground.
hammer [34]

The distance, In feet, from the base of the ladder to the base of the wall is 4.2 ft.

He needs to move the ladder 0.1 ft closer to the base of the building.

The situation forms a right angle triangle.

<h3>Right angle triangle</h3>

Right angle triangle has one of its angles as 90 degrees. The sides and angle can be found using trigonometric ratios.

The length of the ladder is the hypotenuse of the triangle formed. Therefore, the distance, In feet, from the base of the ladder to the base of the wall can be calculated as follows;

cos 65° = adjacent / hypotenuse

cos 65° = d / 10

d = 10 × 0.42261826174

d = 4.22618261741

d = 4.2 ft

She needs to move the ladder so it reached a window 9.6 feet above the ground. Therefore, the distance from the base of the ladder and the wall is as follows;

cos 65 = d / 9.6

d = 9.6 × 0.42261826174

d = 4.05696

d = 4.1

Therefore, he needs to move the ladder 0.1 ft closer to the building.

learn more on right angle triangle here: brainly.com/question/14988069

8 0
3 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
4 years ago
15x+98=105 What is the value of x and please show your work. :) ​
Yuliya22 [10]

Answer:

15x+98=105

      -98    -98

15x=7

/15    /15

x=7/15

Step-by-step explanation:

x=7/15

4 0
3 years ago
The figures in the pair are similar. Find the missing lenth
Varvara68 [4.7K]

Answer:

In two similar triangles, the ratio of their areas is the square of the ratio of their sides. Try this The two triangles below are similar. Drag any orange dot at P,Q,R. Note the ratio of the two corresponding sides and the ratio of the areas.

Step-by-step explanation:

7 0
4 years ago
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