1) 6*10=60, 6*7=42/2=21, 21+60=81
2) 12*12=144, 12*12=144*3.14=452.16/2=226.08, 144+226.08=370.08
3) 14*5=70, 5*10=50, 70+50=120 (maybe)
4) 6*5=30/2=15, 4*3=12/2=6,15+6=21
5) 6*6=36*3.14=113.04/2=56.52, 5*5=25*3.14=78.5/2=39.25, 56.52+39.25=95.77
if right then give brainliest plz
Answer:
Approximately 3.8 seconds
Step-by-step explanation:
H(x)=-16x^2+60x+4
We want to find when the ball hits the ground, or where the zeros are
0 =-16x^2+60x+4
Using the quadratic formula
-b ±sqrt(b^2 -4ac)
---------------------------
2a
-60 ±sqrt(60^2 -4*-16*4)
---------------------------
2(-16)
-60 ±sqrt(3600+256)
---------------------------
-32
-60 ±sqrt(3856)
---------------------------
-32
We want the positive value for time
-60-62.09669879
---------------------------
-32
3.815521837
Approximately 3.8 seconds
The missing exponent is 5^7 your welcome
Answer:
135/14
9 9/14
Step-by-step explanation:
29/7+11/2
