So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Is it −26−(6)^2? If so
−26−(6)^2
= -26 - 36
= - 62
If −26−(6)2 (means 6 times 2) then
= -26 - 12
= -38
Answer:
x = - 1, x = - 11
Step-by-step explanation:
Given
2| x + 6 | - 4 = 6 ( add 4 to both sides )
2|x + 6 | = 10 ( divide both sides by 2 )
| x + 6 | = 5
The absolute value function always gives a positive result, but the expression inside can be positive or negative, that is
x + 6 = 5 or - (x + 6) = 5
solve both
x + 6 = 5 ( subtract 6 from both sides )
x = - 1
or
- (x + 6) = 5 , that is
- x - 6 = 5 ( add 6 to both sides )
- x = 11 ( multiply both sides by - 1 )
x = - 11
Let's find out the gradient (Slope " m ") of line q ;
Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :
Now, plug in the value of gradient ~
here we can clearly observe that, the Area under the curve can easily be represented as :
Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
Let's imagine that we turn the machine on 100 times. (this will make the percent conversion easier)
the chance that works in the morning is 50% of 100 so it will work 50 times.
the chance that it will then continue for the rest of the day is 15% so 15%*50 (the number of times it worked), which is 7.5 times.
our times actually represented percent, so the answer is : 7.5%!
