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RideAnS [48]
3 years ago
12

The number −5 is all of the following except _____.

Mathematics
1 answer:
nirvana33 [79]3 years ago
7 0

Answer:

a real number

Step-by-step explanation: You didn't list the choices- a real number is all positive numbers except 0

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100 Points! Will give brainliest!
disa [49]

-3 ≤ 6x - 6 < 39 (seperate into two inequalities)

6x - 9 ≥ -3

6x - 9 < 39 (solve the inequalities)

x ≥ 1

x < 8 (find the intersection)

x ∈ { 1 , 8 }

6 0
3 years ago
Read 2 more answers
I’m confused please solve it.
Allushta [10]

Answer:

b = 65

Step-by-step explanation:

b is the y- intercept

if you start to graph 6x from the two points that are already given then it'll find the y-intercept which is b

here's the graph

3 0
3 years ago
The figure shown represents a triangular window design. If IKL = JOP, which of
ankoles [38]

ikl=opj

Step-by-step explanation:

triangle is opj

7 0
3 years ago
Can someone please help me I will give out brainliest!!!<br> And 15 POINTS
jenyasd209 [6]

Answer:

<em>a) 15 b) 6 c) -3</em>

Step-by-step explanation:

x - y = 3

a) 5 (x - y) = 5 (3) = 15

b) 2x - 2y = 2 (x - y) = 2 (3) = 6

c) y - x = -1 (x - y) = -1 (3) = -3

5 0
3 years ago
Read 2 more answers
A particular sawdust pile has a base diameter of 25 feet when the height is 20 feet. Find the volume of this sawdust pile when i
Artist 52 [7]

The volume of the sawdust pile is 11,039.06 ft³.

<h3>What is the volume of the pile?
</h3>

The shape of the sawdust pile would be a cone. The diameter is always proportional to its height.

Diameter = k x height

where k is equivalent to the rate of increase of the diameter with respect to the increase in height.

25= k20

k = 25 / 20

k = 1.25

Diameter when height is 30 ft = 1.25x 30 = 35.50 feet

Volume of the sawdust = \frac{1}{3}πr²h

Where:

  • π = 3.14
  • r = radius = diameter / 2 = 35.50 / 2 = 18.75
  • h = 30

\frac{1}{3} x 3.14 x 18.75² x 30 = 11,039.06 ft³

To learn more about the volume of a cone, please check: brainly.com/question/13705125

#SPJ1

4 0
1 year ago
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